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<oembed><version>1.0</version><provider_name>Electrical Riddle</provider_name><provider_url>https://electrical-riddle.com/en</provider_url><author_name>Electrical Riddle</author_name><author_url>https://electrical-riddle.com/en</author_url><title>- Electrical Riddle</title><type>rich</type><width>600</width><height>338</height><html>&lt;blockquote class="wp-embedded-content" data-secret="1EaXW6Mzwg"&gt;&lt;a href="https://electrical-riddle.com/en/forums/reply/1858/"&gt;Reply To: Grounding Riddle No.22 &#x2013; Main Earthing Conductor sizing calculation&lt;/a&gt;&lt;/blockquote&gt;&lt;iframe sandbox="allow-scripts" security="restricted" src="https://electrical-riddle.com/en/forums/reply/1858/embed/#?secret=1EaXW6Mzwg" width="600" height="338" title="&#x201C;Reply To: Grounding Riddle No.22 &#x2013; Main Earthing Conductor sizing calculation&#x201D; &#x2014; Electrical Riddle" data-secret="1EaXW6Mzwg" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"&gt;&lt;/iframe&gt;&lt;script&gt;
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</html><description>That mentioned Equation (which was not written correctly) reflect two basic assumptions a) That all heat will be retained in the conductor (adiabatic process). b) That the product of specific heat (SH) and specific weight (SW), TCAP, is approximately constant because SH increases and SW decreases at about the same rate. For most metals, these &hellip;  Read More &raquo;</description><thumbnail_url>https://electrical-riddle.com/wp-content/uploads/2021/08/1822298283_330.gif</thumbnail_url></oembed>
