{"version":"1.0","provider_name":"Electrical Riddle","provider_url":"https:\/\/electrical-riddle.com\/en","author_name":"Electrical Riddle","author_url":"https:\/\/electrical-riddle.com\/en","title":"- Electrical Riddle","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"RrBh48KCnf\"><a href=\"https:\/\/electrical-riddle.com\/en\/forums\/reply\/1150\/\">Reply To: Protection riddle no.3 &ndash; Short line between power plant and substation<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/electrical-riddle.com\/en\/forums\/reply\/1150\/embed\/#?secret=RrBh48KCnf\" width=\"600\" height=\"338\" title=\"&#8220;Reply To: Protection riddle no.3 &ndash; Short line between power plant and substation&#8221; &#8212; Electrical Riddle\" data-secret=\"RrBh48KCnf\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/electrical-riddle.com\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"Summation Of CT secondaries is the only way in view of the circuit requirement. The need is to input relay with the correct secondary current. Low impedance relay requires less stringent requirement on CTs."}