{"version":"1.0","provider_name":"Electrical Riddle","provider_url":"https:\/\/electrical-riddle.com\/en","author_name":"Electrical Riddle","author_url":"https:\/\/electrical-riddle.com\/en","title":"- Electrical Riddle","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"47gJl18Chd\"><a href=\"https:\/\/electrical-riddle.com\/en\/forums\/reply\/1405\/\">Reply To: Machine Riddle No.5 &#8211; Power Swing Problem<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/electrical-riddle.com\/en\/forums\/reply\/1405\/embed\/#?secret=47gJl18Chd\" width=\"600\" height=\"338\" title=\"&#8220;Reply To: Machine Riddle No.5 &#8211; Power Swing Problem&#8221; &#8212; Electrical Riddle\" data-secret=\"47gJl18Chd\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/electrical-riddle.com\/wp-includes\/js\/wp-embed.min.js\n<\/script>\n","description":"An important consideration in resistance-grounded systems is the power loss in the resistor during line-to-ground faults. The power loss in the grounding resistor is Ir.Er or Ir2.R. Ir and Er are both in terms of normal values per phase. The power loss obtained by their product is therefore in terms of normal value per phase. &hellip;  Read More &raquo;"}