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<oembed><version>1.0</version><provider_name>Electrical Riddle</provider_name><provider_url>https://electrical-riddle.com/fa</provider_url><author_name>Electrical Riddle</author_name><author_url>https://electrical-riddle.com/fa</author_url><title>- Electrical Riddle</title><type>rich</type><width>600</width><height>338</height><html>&lt;blockquote class="wp-embedded-content" data-secret="FcXPVEM2QU"&gt;&lt;a href="https://electrical-riddle.com/fa/forums/reply/1175/"&gt;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Electrical riddle no.6 &ndash; Forces between two current elements and Newton's third law&lt;/a&gt;&lt;/blockquote&gt;&lt;iframe sandbox="allow-scripts" security="restricted" src="https://electrical-riddle.com/fa/forums/reply/1175/embed/#?secret=FcXPVEM2QU" width="600" height="338" title="&#x201C;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Electrical riddle no.6 &ndash; Forces between two current elements and Newton's third law&#x201D; &#x2014; Electrical Riddle" data-secret="FcXPVEM2QU" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"&gt;&lt;/iframe&gt;&lt;script&gt;
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&lt;/script&gt;</html><description>According to electrical engineering experience, two free wires carrying currents can not stable non parallel, and applied electromagnetic torque to each wire rotate them and they will be parallel after short time.Therefor in non parallel configuration of wires we need to assume one supplementary mechanical force in system which we were not considered it. Of &hellip;  &#x627;&#x62F;&#x627;&#x645;&#x647; &#xBB;</description></oembed>
