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<oembed><version>1.0</version><provider_name>Electrical Riddle</provider_name><provider_url>https://electrical-riddle.com/fa</provider_url><author_name>Electrical Riddle</author_name><author_url>https://electrical-riddle.com/fa</author_url><title>- Electrical Riddle</title><type>rich</type><width>600</width><height>338</height><html>&lt;blockquote class="wp-embedded-content" data-secret="HKr2OjiUQL"&gt;&lt;a href="https://electrical-riddle.com/fa/forums/reply/2579/"&gt;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Power Electronic Riddle No.10 &#x2013; Power inverter using IGBT&lt;/a&gt;&lt;/blockquote&gt;&lt;iframe sandbox="allow-scripts" security="restricted" src="https://electrical-riddle.com/fa/forums/reply/2579/embed/#?secret=HKr2OjiUQL" width="600" height="338" title="&#x201C;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Power Electronic Riddle No.10 &#x2013; Power inverter using IGBT&#x201D; &#x2014; Electrical Riddle" data-secret="HKr2OjiUQL" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"&gt;&lt;/iframe&gt;&lt;script&gt;
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&lt;/script&gt;</html><description>A half-bridge voltage-fed IGBT inverter is shown in Figure, whereas Figure below shows the switching voltage and current waves when no snubbers are used (hard switched). Assume that the load is highly inductive and initially Q1 is off so that the lower diode D2 is carrying the full load current IL. When Q1 is turned &hellip;  &#x627;&#x62F;&#x627;&#x645;&#x647; &#xBB;</description><thumbnail_url>https://electrical-riddle.com/wp-content/uploads/2021/08/1563037362_730.gif</thumbnail_url></oembed>
