<?xml version="1.0"?>
<oembed><version>1.0</version><provider_name>Electrical Riddle</provider_name><provider_url>https://electrical-riddle.com/fa</provider_url><author_name>Electrical Riddle</author_name><author_url>https://electrical-riddle.com/fa</author_url><title>- Electrical Riddle</title><type>rich</type><width>600</width><height>338</height><html>&lt;blockquote class="wp-embedded-content" data-secret="lX1Y3HR83z"&gt;&lt;a href="https://electrical-riddle.com/fa/forums/reply/3248/"&gt;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Power Generation Riddle No.8 &#x2013; Transient Stability Of Solar Power&lt;/a&gt;&lt;/blockquote&gt;&lt;iframe sandbox="allow-scripts" security="restricted" src="https://electrical-riddle.com/fa/forums/reply/3248/embed/#?secret=lX1Y3HR83z" width="600" height="338" title="&#x201C;&#x67E;&#x627;&#x633;&#x62E; &#x628;&#x647;: Power Generation Riddle No.8 &#x2013; Transient Stability Of Solar Power&#x201D; &#x2014; Electrical Riddle" data-secret="lX1Y3HR83z" frameborder="0" marginwidth="0" marginheight="0" scrolling="no" class="wp-embedded-content"&gt;&lt;/iframe&gt;&lt;script&gt;
/*! This file is auto-generated */
!function(d,l){"use strict";l.querySelector&amp;&amp;d.addEventListener&amp;&amp;"undefined"!=typeof URL&amp;&amp;(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&amp;&amp;!/[^a-zA-Z0-9]/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret="'+t.secret+'"]'),o=l.querySelectorAll('blockquote[data-secret="'+t.secret+'"]'),c=new RegExp("^https?:$","i"),i=0;i&lt;o.length;i++)o[i].style.display="none";for(i=0;i&lt;a.length;i++)s=a[i],e.source===s.contentWindow&amp;&amp;(s.removeAttribute("style"),"height"===t.message?(1e3&lt;(r=parseInt(t.value,10))?r=1e3:~~r&lt;200&amp;&amp;(r=200),s.height=r):"link"===t.message&amp;&amp;(r=new URL(s.getAttribute("src")),n=new URL(t.value),c.test(n.protocol))&amp;&amp;n.host===r.host&amp;&amp;l.activeElement===s&amp;&amp;(d.top.location.href=t.value))}},d.addEventListener("message",d.wp.receiveEmbedMessage,!1),l.addEventListener("DOMContentLoaded",function(){for(var e,t,s=l.querySelectorAll("iframe.wp-embedded-content"),r=0;r&lt;s.length;r++)(t=(e=s[r]).getAttribute("data-secret"))||(t=Math.random().toString(36).substring(2,12),e.src+="#?secret="+t,e.setAttribute("data-secret",t)),e.contentWindow.postMessage({message:"ready",secret:t},"*")},!1)))}(window,document);
//# sourceURL=https://electrical-riddle.com/wp-includes/js/wp-embed.min.js
&lt;/script&gt;</html><description>According to illustrated PV/IV curve, the slope of curve in B1 is positive and in B2 is negative. It means each decreasing of voltage due to load variation in B2 point can be caused the power/current generation increasing which can restore the system to last position.</description></oembed>
