{"version":"1.0","provider_name":"Electrical Riddle","provider_url":"https:\/\/electrical-riddle.com\/fa","author_name":"Electrical Riddle","author_url":"https:\/\/electrical-riddle.com\/fa","title":"- Electrical Riddle","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"T4Rsy5LROF\"><a href=\"https:\/\/electrical-riddle.com\/fa\/forums\/reply\/1779\/\">\u067e\u0627\u0633\u062e \u0628\u0647: Transformer Question No.34 &#8211; Designing of choke\/reactor<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/electrical-riddle.com\/fa\/forums\/reply\/1779\/embed\/#?secret=T4Rsy5LROF\" width=\"600\" height=\"338\" title=\"&#8220;\u067e\u0627\u0633\u062e \u0628\u0647: Transformer Question No.34 &#8211; Designing of choke\/reactor&#8221; &#8212; Electrical Riddle\" data-secret=\"T4Rsy5LROF\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/electrical-riddle.com\/wp-includes\/js\/wp-embed.min.js\n<\/script>","description":"The design of a linear ac inductor depends upon five related factors: 1 . Desired inductance 2. Applied voltage, (across inductor) 3. Frequency 4. Operating Flux density 5. Temperature Rise With these requirements established, the designer must determine the maximum values for, Bac, which will not produce magnetic saturation, and make trade-offs that will yield &hellip;  \u0627\u062f\u0627\u0645\u0647 \u00bb","thumbnail_url":"https:\/\/electrical-riddle.com\/wp-content\/uploads\/2021\/08\/290044971_251.gif"}