{"version":"1.0","provider_name":"Electrical Riddle","provider_url":"https:\/\/electrical-riddle.com\/fa","author_name":"Electrical Riddle","author_url":"https:\/\/electrical-riddle.com\/fa","title":"- Electrical Riddle","type":"rich","width":600,"height":338,"html":"<blockquote class=\"wp-embedded-content\" data-secret=\"qmAzb58OPW\"><a href=\"https:\/\/electrical-riddle.com\/fa\/forums\/reply\/2931\/\">\u067e\u0627\u0633\u062e \u0628\u0647: Machine Riddle No.40 &#8211; No Load current of Induction motor<\/a><\/blockquote><iframe sandbox=\"allow-scripts\" security=\"restricted\" src=\"https:\/\/electrical-riddle.com\/fa\/forums\/reply\/2931\/embed\/#?secret=qmAzb58OPW\" width=\"600\" height=\"338\" title=\"&#8220;\u067e\u0627\u0633\u062e \u0628\u0647: Machine Riddle No.40 &#8211; No Load current of Induction motor&#8221; &#8212; Electrical Riddle\" data-secret=\"qmAzb58OPW\" frameborder=\"0\" marginwidth=\"0\" marginheight=\"0\" scrolling=\"no\" class=\"wp-embedded-content\"><\/iframe><script>\n\/*! This file is auto-generated *\/\n!function(d,l){\"use strict\";l.querySelector&&d.addEventListener&&\"undefined\"!=typeof URL&&(d.wp=d.wp||{},d.wp.receiveEmbedMessage||(d.wp.receiveEmbedMessage=function(e){var t=e.data;if((t||t.secret||t.message||t.value)&&!\/[^a-zA-Z0-9]\/.test(t.secret)){for(var s,r,n,a=l.querySelectorAll('iframe[data-secret=\"'+t.secret+'\"]'),o=l.querySelectorAll('blockquote[data-secret=\"'+t.secret+'\"]'),c=new RegExp(\"^https?:$\",\"i\"),i=0;i<o.length;i++)o[i].style.display=\"none\";for(i=0;i<a.length;i++)s=a[i],e.source===s.contentWindow&&(s.removeAttribute(\"style\"),\"height\"===t.message?(1e3<(r=parseInt(t.value,10))?r=1e3:~~r<200&&(r=200),s.height=r):\"link\"===t.message&&(r=new URL(s.getAttribute(\"src\")),n=new URL(t.value),c.test(n.protocol))&&n.host===r.host&&l.activeElement===s&&(d.top.location.href=t.value))}},d.addEventListener(\"message\",d.wp.receiveEmbedMessage,!1),l.addEventListener(\"DOMContentLoaded\",function(){for(var e,t,s=l.querySelectorAll(\"iframe.wp-embedded-content\"),r=0;r<s.length;r++)(t=(e=s[r]).getAttribute(\"data-secret\"))||(t=Math.random().toString(36).substring(2,12),e.src+=\"#?secret=\"+t,e.setAttribute(\"data-secret\",t)),e.contentWindow.postMessage({message:\"ready\",secret:t},\"*\")},!1)))}(window,document);\n\/\/# sourceURL=https:\/\/electrical-riddle.com\/wp-includes\/js\/wp-embed.min.js\n<\/script>","description":"Thanks Mr. Hamid. Yes sir, the PF at no load will be small than full load, due to inductive circuit. Once again many thanks for this useful information regarding no load current of the motors."}