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Why strong spring usually is used in high current circuit breakers? Why required forces for operation of circuit breaker shall be increased when its rated current or short circuit capacity is increased?
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As it can be seen from the figure, as the current constricts into a transfer point there is a component of the current that flows in opposite directions and thus the net result is a repelling force trying to force apart the contacts. The repulsion force is given by: F=10-7. I2 . ln (B/a) Newton Where: B = Contact area a = Actual area of contact point With increasing of electrical contact pressures, the concentrated current area (a) can be increased which cause the reduction of repulsion forces. It is difficult however to properly use this formula because of the difficulty in defining the actual contact area. For practical purposes some expressions that yield adequate results have been proposed. For example: F= 0.115 (I/n)2 lb.per finger Or practical relationship which was obtained experimentally with a 3 inch Cu-Cr butt type contact in vacuum is given by the expression: F= 0.885 (I/n)1.51 lb.per finger Where: I = Peak current in kA n = Number of contacts The differences on the force requirements obtained depending on which expression is used serve to point out the uncertainty of the variables involved and the probabilistic nature of the forces. In general the application of higher forces would yield a higher confidence level and a higher probability of withstanding the repulsion forces.